document.write( "Question 510149: factor 64c^2+81-144c \n" ); document.write( "
Algebra.Com's Answer #341725 by Earlsdon(6294)\"\" \"About 
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Factor:
\n" ); document.write( "\"64c%5E2%2B81-144c\" Rewrite in standard form:
\n" ); document.write( "\"64c%5E2-144c%2B81\" Notice that the first and last terms are perfect squares: \"64+=+8%5E2\" and \"81+=+9%5E2\" so try...
\n" ); document.write( "\"%288c-9%29%288c-9%29\" Check by multiplying these factors to see that you get the original trinomial.
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