document.write( "Question 510000: A radiator contains 13 quarts of fluid, 25% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 50% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #341699 by ankor@dixie-net.com(22740)\"\" \"About 
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A radiator contains 13 quarts of fluid, 25% of which is antifreeze.
\n" ); document.write( " How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 50% antifreeze?
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\n" ); document.write( "Let x = amt of original antifreeze to be drained, and the amt of pure antifreeze to be added
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\n" ); document.write( "a simple equation
\n" ); document.write( ".25(13-x) + x = .50(13)
\n" ); document.write( "3.25 - .25x + x = 6.5
\n" ); document.write( "-.25x + 1x = 6.5 - 3.25
\n" ); document.write( ".75x = 3.25
\n" ); document.write( "x = 3.25/.75
\n" ); document.write( "x = 4\"1%2F3\" quarts removed, then the same amt of pure antifreeze added
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