document.write( "Question 509962: for y=2cos(4x-pi/3)\r
\n" ); document.write( "\n" ); document.write( "find
\n" ); document.write( "a)amplitude
\n" ); document.write( "b)period
\n" ); document.write( "c)phase shift
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Algebra.Com's Answer #341694 by lwsshak3(11628)\"\" \"About 
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for y=2cos(4x-pi/3)
\n" ); document.write( "find
\n" ); document.write( "a)amplitude
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\n" ); document.write( "c)phase shift
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\n" ); document.write( "Standard form of equation for cosine: y=Acos(Bx-C), A=amplitude, Period=2π/B,
\n" ); document.write( "Phase shift=C/B
\n" ); document.write( "For given problem:
\n" ); document.write( "a)amplitude: 2
\n" ); document.write( "b)period: 2π/B=2π/4=π/2
\n" ); document.write( "c)phase shift: C/B=(π/3)/4=π/12 (shift to the right)
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