document.write( "Question 509792: mary began walking home from school, heading south at a rate of 4 mph. Sharon left school at the same time heading north at 6 mph. how long will it take for them to be 3 miles apart?
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Algebra.Com's Answer #341690 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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mary began walking home from school, heading south at a rate of 4 mph.
\n" ); document.write( " Sharon left school at the same time heading north at 6 mph.
\n" ); document.write( " how long will it take for them to be 3 miles apart?
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\n" ); document.write( "Let t = time (in hrs) for them to be 3 mi apart
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\n" ); document.write( "Write a distance equation; dist = speed*time
\n" ); document.write( "4t + 6t = 3
\n" ); document.write( "10t = 3
\n" ); document.write( "t = $\"3%2F10\"$
\n" ); document.write( "t = .3 hrs (.3*60 = 18 min)
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\n" ); document.write( "Check by finding the distance each walked
\n" ); document.write( ".3(4) = 1.2 mi
\n" ); document.write( ".3(6) = 1.8 mi
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\n" ); document.write( "total: 3 mi \n" ); document.write( "

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