document.write( "Question 51203This question is from textbook Beginning Algebra
\n" ); document.write( ": Can someone solve this problem for me?\r
\n" ); document.write( "\n" ); document.write( "solve by using quadratic formula\r
\n" ); document.write( "\n" ); document.write( "x^2-4x-60=0
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Algebra.Com's Answer #34169 by mathchemprofessor(65)\"\" \"About 
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x^2-4x-60=0
\n" ); document.write( "This is of the form,
\n" ); document.write( "ax^2+bx+c=0
\n" ); document.write( "Comparing the above two equations,
\n" ); document.write( "a=1,b=-4, c=-60
\n" ); document.write( "Quadradic formula:
\n" ); document.write( "x =(-b+sqrt(b^2-4ac))/2a
\n" ); document.write( "Substituting the values of a,b and c, from the given equation,
\n" ); document.write( "x=(-(-4) ħsqrt(-4)^2-4(1)(-60))/2*1
\n" ); document.write( "=( 4ħsqrt(16+240))/2*1
\n" ); document.write( "= (4ħsqrt256)/2
\n" ); document.write( "= (4ħ16)/2
\n" ); document.write( "So, x= (4+16)/2 or x = (4-16)/2
\n" ); document.write( " x=20/2=10 or x= -12/2=-6\r
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