document.write( "Question 509905: A chemist work on a new project needs 12liters of 50% acid solution, The stockroom only has 40% and 70% solutions. how much of each solution should be mixed together to form 12 liters of a 50% solution. \n" ); document.write( "
Algebra.Com's Answer #341651 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Solution A \n" ); document.write( "Concentration = 40%=0.4 \n" ); document.write( "Amount = x \n" ); document.write( "======================= \n" ); document.write( "Solution B \n" ); document.write( "Concentration = 70%=0.7 \n" ); document.write( "Amount = 12-x \n" ); document.write( "========================== \n" ); document.write( "Resultant Solution \n" ); document.write( "Concentration = 50%=0.5 \n" ); document.write( "Amount = 12 liters \n" ); document.write( "======================================== \n" ); document.write( "(Concentration of A * Amount of A)+(Concentration of B * Amount of B)=(Concentration of Resultant * Amount of Resultant) \n" ); document.write( "========================================== \n" ); document.write( "0.4x+0.7(12-x)=0.5*12 \n" ); document.write( "0.4x+8.4-0.7x=6 \n" ); document.write( "-0.3x=6-8.4 \n" ); document.write( "-0.3x=-2.4 \n" ); document.write( "Divide by -0.3 both sides \n" ); document.write( "-0.3x/-0.3=-2.4/-0.3 \n" ); document.write( "x=8 \n" ); document.write( "========================================== \n" ); document.write( "Amount of solution A = x = 8 liters \n" ); document.write( "Amount of solution B = 12-x = 12-8 = 4 liters\r \n" ); document.write( "\n" ); document.write( "Conclusion \n" ); document.write( "========== \n" ); document.write( "chemist needs to mix 8 liters of 40% and 4 liters of 70% solutions to get 12 liters of a 50% solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |