document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=509748>Question 509748</A>: <I><SPAN STYLE=\"word-break: break-all;\"> y+4=-2/3(x-3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341610 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341610\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y+4=-2/3(x-3)<BR>\n" );
document.write( "Now the way this is written makes it a little confusing, specifically:\r<BR>\n" );
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document.write( "Do we mean y+4=-2 over 3(x-3) or do we mean:<BR>\n" );
document.write( "y+4=(-2/3) times (x-3)?  I will assume the latter but the correct use of parens will frequently clarify the meaning.<BR>\n" );
document.write( "y+4=(-2/3)(x-3)  multiply each term by 3<BR>\n" );
document.write( "3y+12=-2(x-3)<BR>\n" );
document.write( "3y+12=-2x+6 subtract 12 from each side<BR>\n" );
document.write( "3y=-2x-6<BR>\n" );
document.write( "y=(-2/3)x-2 This is now in standard slope-intercept form<BR>\n" );
document.write( "slope=-2/3<BR>\n" );
document.write( "y-intercept=-2\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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