document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=509747>Question 509747</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of the side of a rectangular desk is given by 2x - 7y cm. The length of the front is given by 2x + 7y cm. What is an algebraic expression for the area of the top of the rectangular desk? Include correct units as part of your answer.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341609 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341609\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area(A) of a rectangle equals Length(L) times Width(W) or A=L*W\r<BR>\n" );
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document.write( "Length of rectangle=(2x-7y)cm<BR>\n" );
document.write( "Width of rectangle=(2x+7y)cm\r<BR>\n" );
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document.write( "Area of the top=(2x-7y)cm*(2x+7y)cm using FOIL, we get<BR>\n" );
document.write( "Area of top=(4x^2+14xy-14xy-49y^2)cm^2<BR>\n" );
document.write( "Area of top=(4x^2-49y^2)cm^2 \r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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