document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=509746>Question 509746</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 44 yards. The length is 2 yards more than three times the width.\r<BR>\n" );
document.write( "\n" );
document.write( "Find the width of the rectangle.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341608 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341608\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter(P) of a rectangle equals 2* Length(L) plus 2*Width(W) or P=2L+2W\r<BR>\n" );
document.write( "\n" );
document.write( "Let W=width<BR>\n" );
document.write( "Then L=3W+2<BR>\n" );
document.write( "soooo,<BR>\n" );
document.write( "P=2L+2W or<BR>\n" );
document.write( "44=2(3W+2)+2W<BR>\n" );
document.write( "6W+4+2W=44<BR>\n" );
document.write( "8W=40<BR>\n" );
document.write( "W=5 yards-------------------width of rectangle<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "L=3W+2=3*5+2=17 yards<BR>\n" );
document.write( "44=2*17+2*5<BR>\n" );
document.write( "44=34+10<BR>\n" );
document.write( "44=44\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );