document.write( "Question 506079: find three consecutive integers such that 4 times the sum of the last two is 2 greater than 10 times the first. I don't understand how to find the sum of the last two. \n" ); document.write( "

Algebra.Com's Answer #341587 by Maths68(1474) $\"\"$ $\"About$

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Let
\n" ); document.write( "1st Integer = x
\n" ); document.write( "2nd Integer = x+1
\n" ); document.write( "3rd Integer = x+2
\n" ); document.write( "===============================================
\n" ); document.write( "Given
\n" ); document.write( "4((x+1)+(x+2))=10(x)+2
\n" ); document.write( "4(x+1+x+2)=10x+2
\n" ); document.write( "4(2x+3)=10x+2
\n" ); document.write( "8x+12=10x+2
\n" ); document.write( "8x-10x=+2-12
\n" ); document.write( "-2x=-10
\n" ); document.write( "-2x/-2=-10/-2
\n" ); document.write( "x=5
\n" ); document.write( "===============================================
\n" ); document.write( "1st Integer = x =5
\n" ); document.write( "2nd Integer = x+1 =5+1=6
\n" ); document.write( "3rd Integer = x+2=5+2=7
\n" ); document.write( "================================================
\n" ); document.write( "Check
\n" ); document.write( "4(6+7)=10(5)+2
\n" ); document.write( "4(13)=50+2
\n" ); document.write( "52=52
\n" ); document.write( " \n" ); document.write( "

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