document.write( "Question 505978: find two consecutive integers whose product is 7 more than the square of the smaller number \n" ); document.write( "

Algebra.Com's Answer #341585 by Maths68(1474) $\"\"$ $\"About$

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Let
\n" ); document.write( "Smaller integer = x
\n" ); document.write( "Greater integer= x+1
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\n" ); document.write( "Given
\n" ); document.write( "x*(x+1)=x^2+7
\n" ); document.write( "x*(x+1)=x^2+7
\n" ); document.write( "x^2+x=x^2+7
\n" ); document.write( "x^2-x^2+x=7
\n" ); document.write( "x=7
\n" ); document.write( "=====================================
\n" ); document.write( "Smaller integer = x =7
\n" ); document.write( "Greater = x+1 = 7+1=8
\n" ); document.write( "=========================================
\n" ); document.write( "Check
\n" ); document.write( "8*7=7^2+7
\n" ); document.write( "56=49+7
\n" ); document.write( "56=56
\n" ); document.write( " \n" ); document.write( "

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