document.write( "Question 506675: Find three consecutive even itegers such that four times the first minus the third is six more than twice the second. \n" ); document.write( "
Algebra.Com's Answer #341583 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "1st Interger = x+2
\n" ); document.write( "2nd Interger = x+4
\n" ); document.write( "3rd t Interger = x+6
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\n" ); document.write( "Given
\n" ); document.write( "4(x+2)-(x+6)=2(x+4)+6
\n" ); document.write( "4x+8-x-6=2x+8+6
\n" ); document.write( "3x+2=2x+14
\n" ); document.write( "3x-2x=14-2
\n" ); document.write( "x=12
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\n" ); document.write( "1st Interger = x+2 =12+2 =14
\n" ); document.write( "2nd Interger = x+4=12+4=16
\n" ); document.write( "3rd t Interger = x+6=12+6=18
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\n" ); document.write( "Check
\n" ); document.write( "4(x+2)-(x+6)=2(x+4)+6
\n" ); document.write( "4(14)-18=2(16)+6
\n" ); document.write( "56-18=32+6
\n" ); document.write( "38=38
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