document.write( "Question 506675: Find three consecutive even itegers such that four times the first minus the third is six more than twice the second. \n" ); document.write( "
Algebra.Com's Answer #341583 by Maths68(1474) You can put this solution on YOUR website! Let \n" ); document.write( "1st Interger = x+2 \n" ); document.write( "2nd Interger = x+4 \n" ); document.write( "3rd t Interger = x+6 \n" ); document.write( "===================================================== \n" ); document.write( "Given \n" ); document.write( "4(x+2)-(x+6)=2(x+4)+6 \n" ); document.write( "4x+8-x-6=2x+8+6 \n" ); document.write( "3x+2=2x+14 \n" ); document.write( "3x-2x=14-2 \n" ); document.write( "x=12 \n" ); document.write( "=================================================== \n" ); document.write( "1st Interger = x+2 =12+2 =14 \n" ); document.write( "2nd Interger = x+4=12+4=16 \n" ); document.write( "3rd t Interger = x+6=12+6=18 \n" ); document.write( "=================================================== \n" ); document.write( "Check \n" ); document.write( "4(x+2)-(x+6)=2(x+4)+6 \n" ); document.write( "4(14)-18=2(16)+6 \n" ); document.write( "56-18=32+6 \n" ); document.write( "38=38 \n" ); document.write( " \n" ); document.write( " |