document.write( "Question 506974: find four consecutive numbers such that the sum of the first three numbers is twelve more than the fourth number \n" ); document.write( "

Algebra.Com's Answer #341582 by Maths68(1474) $\"\"$ $\"About$

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Let
\n" ); document.write( "1st Integer = x
\n" ); document.write( "2nd Integer = x+1
\n" ); document.write( "3rd Integer = x+2
\n" ); document.write( "4th integer = x+3
\n" ); document.write( "=======================================
\n" ); document.write( "Given
\n" ); document.write( "x+x+1+x+2=(x+3)+12
\n" ); document.write( "3x+3=x+3+12
\n" ); document.write( "3x+3=x+15
\n" ); document.write( "3x=x+15-3
\n" ); document.write( "3x=x+12
\n" ); document.write( "3x-x=12
\n" ); document.write( "2x=12
\n" ); document.write( "x=12/2
\n" ); document.write( "x=6
\n" ); document.write( "========================================
\n" ); document.write( "1st Integer = x = 6
\n" ); document.write( "2nd Integer = x+1 = 6+1 = 7
\n" ); document.write( "3rd Integer = x+2 =6+2= 8
\n" ); document.write( "4th integer = x+3=6+3=9
\n" ); document.write( "=====================================
\n" ); document.write( "Check
\n" ); document.write( "x+(x+1)+(x+2)=(x+3)+12
\n" ); document.write( "6+7+8=9+12
\n" ); document.write( "21=21
\n" ); document.write( " \n" ); document.write( "

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