document.write( "Question 508187: Find three consecutive integers such that the sum of twice the first number and three times the third number is fourteen more than four times the second number (problem written on worksheet) \n" ); document.write( "
Algebra.Com's Answer #341571 by Maths68(1474)\"\" \"About 
You can put this solution on YOUR website!
Let
\n" ); document.write( "1st Integer = x
\n" ); document.write( "2nd Integer = x+1
\n" ); document.write( "3rd Integer = x+2
\n" ); document.write( "======================================
\n" ); document.write( "2(x)+3(x+2)=14+4(x+1)
\n" ); document.write( "2x+3x+6=14+4x+4
\n" ); document.write( "5x+6=4x+18
\n" ); document.write( "5x-4x=18-6
\n" ); document.write( "x=12
\n" ); document.write( "========================================
\n" ); document.write( "1st Integer = x = 12
\n" ); document.write( "2nd Integer = x+1 = 12+1 = 13
\n" ); document.write( "3rd Integer = x+2 = 12+2 = 14
\n" ); document.write( "=============================================
\n" ); document.write( "Check
\n" ); document.write( "2(x)+3(x+2)=14+4(x+1)
\n" ); document.write( "2(12)+3(14)=14+4(13)
\n" ); document.write( "24+42=14+52
\n" ); document.write( "66=66
\n" ); document.write( "
\n" ); document.write( "
\n" );