document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=509542>Question 509542</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if i have a proof with with the given being AL=SK and i am trying to prove AS=LK and the statements are <BR>\n" );
document.write( "1 AL=SK<BR>\n" );
document.write( "2 LS=LS<BR>\n" );
document.write( "3 AL+LS=SK+LS<BR>\n" );
document.write( "4 AL+LS=AS<BR>\n" );
document.write( "5 SK+LS=LK<BR>\n" );
document.write( "6 AS=LK<BR>\n" );
document.write( "what would be the reasons for all the statements? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341564 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341564\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. Given<BR>\n" );
document.write( "2. This is pretty trivial. Sometimes called the reflexive property.<BR>\n" );
document.write( "3. We can add LS to both sides (addition property of equality).<BR>\n" );
document.write( "4. If AL, LS are collinear then this is true.<BR>\n" );
document.write( "5. If SK, LS are collinear then this is true.<BR>\n" );
document.write( "6. Take #3, replace AL+AS with AS and SK+LS with LK. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );