document.write( "Question 509652: how many liters of a 25% alcohol solution must be mixed with a 12% solution to get 13L of a 15% solution? \n" ); document.write( "
Algebra.Com's Answer #341539 by mananth(16946)![]() ![]() You can put this solution on YOUR website! ---------percent ---------------- quantity \n" ); document.write( "Alcohol I 25 ---------------- x liters \n" ); document.write( "Alcohol II ---------------- 13 - x liters \n" ); document.write( "Mixture ---------------- 13 \n" ); document.write( " \n" ); document.write( "25x+12(13-x)=15*13 \n" ); document.write( " \n" ); document.write( "25x+156-12x=195 \n" ); document.write( "25x-12x=195-156 \n" ); document.write( "13x=39 \n" ); document.write( "/ 13 \n" ); document.write( " x = 3 liters 25.00% Alcohol I \n" ); document.write( " 10 liters 12.00% Alcohol II \n" ); document.write( " \n" ); document.write( " |