document.write( "Question 509652: how many liters of a 25% alcohol solution must be mixed with a 12% solution to get 13L of a 15% solution? \n" ); document.write( "
Algebra.Com's Answer #341539 by mananth(16946)\"\" \"About 
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---------percent ---------------- quantity
\n" ); document.write( "Alcohol I 25 ---------------- x liters
\n" ); document.write( "Alcohol II ---------------- 13 - x liters
\n" ); document.write( "Mixture ---------------- 13
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\n" ); document.write( "25x+12(13-x)=15*13
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\n" ); document.write( "25x+156-12x=195
\n" ); document.write( "25x-12x=195-156
\n" ); document.write( "13x=39
\n" ); document.write( "/ 13
\n" ); document.write( " x = 3 liters 25.00% Alcohol I
\n" ); document.write( " 10 liters 12.00% Alcohol II
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