document.write( "Question 509431: I am stuck on a problem. My algebra teacher told us that we have to check it and show all our work and steps, and I can't get it right.
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document.write( "2(x-5+3x)=14\r
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document.write( "I've tried...
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document.write( "2(x-5+3x)=14
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document.write( "2x-10+6x=14
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document.write( "2x-2x-10+6x-2x=14
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document.write( "-10+4x=14
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document.write( "-10+10+4x=14+10
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document.write( "4x=24
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document.write( "4x/4=24/4
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document.write( "x=6\r
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document.write( "Then, when I check it I must be doing it wrong or don't have the right answer.\r
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document.write( "2(6-5+3*6)=14
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document.write( "12-10+6*12=14
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document.write( "12-10+72=14
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document.write( "2+72=14
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document.write( "74=14\r
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document.write( "It's supposed to be 14 on both sides, but I do not understand it. All of my other problems I got right, but I just for some reason do not understand this question. Please help me as soon as possible, thanks. \n" );
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Algebra.Com's Answer #341452 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 2(x-5+3x)=14 \n" ); document.write( "I've tried... \n" ); document.write( "2(x-5+3x)=14 \n" ); document.write( "2x-10+6x=14 \n" ); document.write( "2x-2x-10+6x-2x=14 \n" ); document.write( "---------- \n" ); document.write( "You subtracted 2x from the left side, but not the right side. \n" ); document.write( "---------- \n" ); document.write( "2(x-5+3x)=14 \n" ); document.write( "Divide by 2 \n" ); document.write( "(x-5+3x) = 7 \n" ); document.write( "4x-5 = 7 \n" ); document.write( "Add 5 \n" ); document.write( "4x = 12 \n" ); document.write( "x = 3 \n" ); document.write( " \n" ); document.write( " |