document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=509390>Question 509390</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The larger of the two numbers is twice the smaller. If the smaller number is increased by 4, the result is 6 less than the larger number. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341407 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341407\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the larger number.  Let y be the smaller number\r<BR>\n" );
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document.write( "x = 2y<BR>\n" );
document.write( "y + 4 = x - 6\r<BR>\n" );
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document.write( "Sub 2y in for x.\r<BR>\n" );
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document.write( "y + 4 = 2y - 6\r<BR>\n" );
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document.write( "y = 10\r<BR>\n" );
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document.write( "Sub y =10 back into either original equation\r<BR>\n" );
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document.write( "x = 2*10 \r<BR>\n" );
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document.write( "x = 20\r<BR>\n" );
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document.write( "So the numbers are 10 and 20. </SPAN>\n" );
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