document.write( "Question 509310: Wilbur left the hardware store and traveled toward the recycling plant at an average speed of 33km/h. Mary left two hours later and traveled in the same direction but with an average speed of 55km/h. How long did Wilbur travel before Mary caught up?
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Algebra.Com's Answer #341384 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Wilbur left the hardware store and traveled toward the recycling plant at an average speed of 33km/h. Mary left two hours later and traveled in the same direction but with an average speed of 55km/h. How long did Wilbur travel before Mary caught up?\r \n" ); document.write( "\n" ); document.write( "----- \n" ); document.write( "Wilbur DATA: \n" ); document.write( "rate = 33 km/h ; time = t hrs ; distance = 33t km \n" ); document.write( "-------------- \n" ); document.write( "Mary DATA: \n" ); document.write( "rate = 55 km/h ; time = t-2 hrs ; distance 55(t-2) km \n" ); document.write( "------ \n" ); document.write( "Equation: \n" ); document.write( "distance = distance \n" ); document.write( "33t = 55(t-2) \n" ); document.write( "33t = 55t-110 \n" ); document.write( "22t = 110 \n" ); document.write( "t = 5 hrs (time for Mary to catch up to Wilbur) \n" ); document.write( "================================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |