document.write( "Question 509310: Wilbur left the hardware store and traveled toward the recycling plant at an average speed of 33km/h. Mary left two hours later and traveled in the same direction but with an average speed of 55km/h. How long did Wilbur travel before Mary caught up?
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Algebra.Com's Answer #341384 by stanbon(75887)\"\" \"About 
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Wilbur left the hardware store and traveled toward the recycling plant at an average speed of 33km/h. Mary left two hours later and traveled in the same direction but with an average speed of 55km/h. How long did Wilbur travel before Mary caught up?\r
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\n" ); document.write( "Wilbur DATA:
\n" ); document.write( "rate = 33 km/h ; time = t hrs ; distance = 33t km
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\n" ); document.write( "Mary DATA:
\n" ); document.write( "rate = 55 km/h ; time = t-2 hrs ; distance 55(t-2) km
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\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "33t = 55(t-2)
\n" ); document.write( "33t = 55t-110
\n" ); document.write( "22t = 110
\n" ); document.write( "t = 5 hrs (time for Mary to catch up to Wilbur)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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