document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=509281>Question 509281</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Margo has 40 millimeters of 25% solution. how many millimeters of 60% solution should she add to obtain the required 30% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341372 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Margo has 40 millimeters of 25% solution. how many millimeters of 60% solution should she add to obtain the required 30% solution?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "active + active = active<BR>\n" );
document.write( "0.25*40 + 0.60x = 0.30(40+x)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "25*40 + 60x = 30*40 + 30x<BR>\n" );
document.write( "30x = 5*40<BR>\n" );
document.write( "----<BR>\n" );
document.write( "x = (4/3)5 = 20/3 = 6 2/3 ml (amt of 60% solution needed)<BR>\n" );
document.write( "==================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "===============  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );