document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=51193>Question 51193</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If you have a rectangle thats 30 inches high and 40 inches wide. What is the diagonal measurement </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34135 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34135\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE DIAGONAL OF A RECTANGLE FORMS A RIGHT TRIANGLE THUS WE HAVE A WAY TO FIND THE DIAGONAL OR THE HYPOTENUSE (LONG SIDE) OF THE TRIANGLE.\r<BR>\n" );
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document.write( "IT'S CALLED THE PYTHAGORIAN THEROM A^2+B^2=C^2. WE HAVE THE A & B VALUES <BR>\n" );
document.write( "(30 & 40) NOW WE SOLVE FOR C THE LONG SIDE. 30^2+40^2=C^2 OR 900+1600=C^2 OR <BR>\n" );
document.write( "C^2=2500 OR C=SQRT2500 OR C=50 INCHES FOR THE DIAGONAL. </SPAN>\n" );
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