document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=51189>Question 51189</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having a hard time understanding how to solve this problem.\r<BR>\n" );
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document.write( "John has 300 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). He wants to maximize the area of his patio (area of a rectangle is length times width). What should the dimensions of the patio be, and show how the maximum area of the patio is calculated from the algebraic equation.  \r<BR>\n" );
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document.write( "	Show clearly the algebraic steps which prove your dimensions are the maximum area which can be obtained. Use the vertex form to find the maximum area.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34133 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L+2W=300 OR 2(L+W)=300 OR (L+W)=300/2 OR L+W=150 THUS TO MAXIMIZE THE AREA L SHOULD = W SO L&W ARE 75 FEET. <BR>\n" );
document.write( "THE MAXIMUM AREA WITH THE MINIMUM PERIMETER IS A SQUARE (ALL SIDES ARE EQUAL). </SPAN>\n" );
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