document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=51177>Question 51177</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, I have a problem that has been answered here already. The problem is, I don't quite understand how he arrived at the answer. The problem and answer is here: http://www.algebra.com/cgi-bin/jump-to-question.mpl?question=19628\r<BR>\n" );
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document.write( "The original question is: Suppose that the length of a rectangle is one and one-third times as long as its width. The area of the rectangle is 48 square centimeters. Find the length and width of the rectangle.\r<BR>\n" );
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document.write( "The answer given is:<BR>\n" );
document.write( "LET WIDTH =W<BR>\n" );
document.write( "LENGTH=one and one-third times as long as its width.=(1 and 1/3)(W)..=(4/3)(W).<BR>\n" );
document.write( "=4W/3<BR>\n" );
document.write( "SO AREA =L*W=(4W/3)*W=48<BR>\n" );
document.write( "W*W=48*3/4=36<BR>\n" );
document.write( "W=6 CM<BR>\n" );
document.write( "L=4W/3=4*6/3=8 CM\r<BR>\n" );
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document.write( "I understand most of it, until the line w*w=48*3/4=36 , I'm not sure I understand how he turned 4/3 into 3/4 and multiplied it by 48. I thought one could only add or subtract when bringing a fraction across? Sorry if this is a dumb question. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34132 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34132\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (4W/3)*W=48\r<BR>\n" );
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document.write( "(4/3)W*W = 48<BR>\n" );
document.write( "Now multiply both sides by (3/4) which is the reciprocal of (4/3)<BR>\n" );
document.write( "to get;<BR>\n" );
document.write( "(3/4)(4/3)W*W = 48*(3/4)<BR>\n" );
document.write( "Do you see that (3/4)(4/3)= 1 ?<BR>\n" );
document.write( "W*W=48*(3/4)<BR>\n" );
document.write( "W*W=36<BR>\n" );
document.write( "W=6 CM<BR>\n" );
document.write( "L=4W/3=4*6/3=8 CM \r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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