document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=509172>Question 509172</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me Find the value of 'a' so the equation 4x-3a=2(x+a) has the solution x=10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341317 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341317\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the value of 'a' so the equation 4x-3a=2(x+a) has the solution x=10<BR>\n" );
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document.write( "Sub 10 for x, solve for a.<BR>\n" );
document.write( "4x-3a=2(x+a)<BR>\n" );
document.write( "4*10 - 3a = 2(10-a)<BR>\n" );
document.write( "40 - 3a = 20 - 2a<BR>\n" );
document.write( "a = 20<BR>\n" );
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