document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=509167>Question 509167</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log(16)x=-1/2...how to solve for x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341298 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341298\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The exponentiate (by base 16) both sides of the equation:\r<BR>\n" );
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document.write( "16^(log(16)(x)) =  16^(-1/2)<BR>\n" );
document.write( "x =  16^(-1/2)<BR>\n" );
document.write( "x = 1/(16^(1/2))<BR>\n" );
document.write( "x = 1/sqrt(16)<BR>\n" );
document.write( "x = 1/4 <-------Answer </SPAN>\n" );
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