document.write( "Question 509148: How would you simplify 5/6+2/3*3/4-1/4*2/5 to equal 37/30? I tried it and got 82/30.
\n" ); document.write( "This is how I did it:\r
\n" ); document.write( "\n" ); document.write( "5/6+2/3*3/4-1/4*2/5
\n" ); document.write( "I canceled the threes out and got 1*2 then I also cross cancelled the 2 and 4 making it a 1 and 2, I did that again to the 1/4 and the 2/5 leaving me with this.
\n" ); document.write( "5/6+2-1/10
\n" ); document.write( "after that I found the lcd which is 30
\n" ); document.write( "I Plug that in leaving me with this
\n" ); document.write( "5/6=25/30
\n" ); document.write( "2/1=60/30
\n" ); document.write( "1/10=3/30
\n" ); document.write( "when you plug those in to the equation they equal 82/30
\n" ); document.write( "the answer is suppose to be 37/30
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Algebra.Com's Answer #341279 by swincher4391(1107)\"\" \"About 
You can put this solution on YOUR website!
Let's add some parenthesis to emphasize order of operations here.\r
\n" ); document.write( "\n" ); document.write( "5/6+(2/3*3/4)-(1/4*2/5)\r
\n" ); document.write( "\n" ); document.write( "Left most parenthesis:\r
\n" ); document.write( "\n" ); document.write( "(2/3) * (3/4) cancel out the threes to get (2/4) which reduces to 1/2.\r
\n" ); document.write( "\n" ); document.write( "Right most parenthesis\r
\n" ); document.write( "\n" ); document.write( "(1/4) * (2/5) cancel out the 2, reduce the 4 to a 2 to get (1/(2*5)) = 1/10.\r
\n" ); document.write( "\n" ); document.write( "so we have (5/6) + (1/2) - (1/10)\r
\n" ); document.write( "\n" ); document.write( "Least Common Multiple of 6,12 and 10 is 60.\r
\n" ); document.write( "\n" ); document.write( "(50/60) + (30/60) - (6/60) = 74/60 (reduces to) 37/30 <---- Answer
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