document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=509032>Question 509032</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sandy has an investment account with shares in two companies, SMT and KLR. At the end of June, when each share of SMT was worth $9 and each share of KLR was worth $8, Sandys account was worth $1600. Three months later, SMT was worth $7 a share, KLR was worth $16 a share, and Sandys account was worth $2320. Find the number of shares that Sandy owns for each of the two companies and determine the value of her account when SMT is priced at $11 a share and KLR is priced at $10 a share </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341256 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341256\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x = number of shares of SMT<BR>\n" );
document.write( "let y = number of shares of KLR\r<BR>\n" );
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document.write( "9x + 8y = 1600 (first equation)<BR>\n" );
document.write( "7x + 16y = 2320 (second equation)\r<BR>\n" );
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document.write( "solve these 2 equations simultaneously to get the value of x and  y.\r<BR>\n" );
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document.write( "multiply first equation by 2 to get:<BR>\n" );
document.write( "2 * (9x + 8y) = 2 * 1600 which becomes:<BR>\n" );
document.write( "18x + 16y = 3200 (third equation)\r<BR>\n" );
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document.write( "subtract second equation from third equation to get:<BR>\n" );
document.write( "18x + 16y = 3200 minus:<BR>\n" );
document.write( "7x + 16y = 2320 becomes:<BR>\n" );
document.write( "11x = 880<BR>\n" );
document.write( "divide both sides of this equation by 11 to get:<BR>\n" );
document.write( "x = 80\r<BR>\n" );
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document.write( "substitute 80 for x in first equation to get:<BR>\n" );
document.write( "720 + 8y = 1600<BR>\n" );
document.write( "subtract 720 from both sides of this equation to get:<BR>\n" );
document.write( "8y = 1600 - 720 = 880<BR>\n" );
document.write( "divide both sides of this equation to get:<BR>\n" );
document.write( "y = 110\r<BR>\n" );
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document.write( "you have:<BR>\n" );
document.write( "x = 80 <BR>\n" );
document.write( "y = 110\r<BR>\n" );
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document.write( "this means that:<BR>\n" );
document.write( "number of shares of SMT = 80<BR>\n" );
document.write( "number of shares of KLR = 110\r<BR>\n" );
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document.write( "plug these values into your original equations to confirm they are good.\r<BR>\n" );
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document.write( "9x + 8y = 1600 (first equation)<BR>\n" );
document.write( "7x + 16y = 2320 (second equation)\r<BR>\n" );
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document.write( "become:\r<BR>\n" );
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document.write( "9*80 + 8*110 = 1600 (first equation)<BR>\n" );
document.write( "7*80 + 16*110 = 2320 (second equation)\r<BR>\n" );
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document.write( "simplify to get:\r<BR>\n" );
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document.write( "1600 = 1600 (first equation)<BR>\n" );
document.write( "2320 = 2320 (second equation)\r<BR>\n" );
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document.write( "values are confirmed to be good.\r<BR>\n" );
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document.write( "when SMT is equal to $11 a share and KLR is equal to $10 a share, the equation becomes:\r<BR>\n" );
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document.write( "11*80 + 10*110 = 880 + 1100 = $1980\r<BR>\n" );
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document.write( "that's your answer.<BR>\n" );
document.write( "number of shares of SMT is 80<BR>\n" );
document.write( "number of shares of KLR is 110<BR>\n" );
document.write( "value of portfolio when SMT is $11 a share and KLR is $10 a share is $1980.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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