document.write( "Question 508963: Find three consecutive even integers such that the sum of five times the first, six times the second and seven times the third is 148 \n" ); document.write( "
Algebra.Com's Answer #341223 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "1st Interger = x+2 \n" ); document.write( "2nd Integer = x+4 \n" ); document.write( "3rd Integer = x+6 \n" ); document.write( "--------------------------------------- \n" ); document.write( "Given \n" ); document.write( "5(x+2)+6(x+4)+7(x+6)=148 \n" ); document.write( "5x+10+6x+24+7x+42=148 \n" ); document.write( "18x+76=148 \n" ); document.write( "18x=148-76 \n" ); document.write( "18x=72 \n" ); document.write( "18x/18=72/18 \n" ); document.write( "x=4 \n" ); document.write( "-------------------------------------- \n" ); document.write( "1st Integer = x+2 =4+2=6 \n" ); document.write( "2nd Integer = x+4 = 4+4=8 \n" ); document.write( "3rd Integer = x+6 = 4+6=10 \n" ); document.write( "--------------------------------------- \n" ); document.write( "Check \n" ); document.write( "(5*6)+6*(8)+7*(10)=148 \n" ); document.write( "30+48+70=148 \n" ); document.write( "148=148 \n" ); document.write( " \n" ); document.write( " |