document.write( "Question 508963: Find three consecutive even integers such that the sum of five times the first, six times the second and seven times the third is 148 \n" ); document.write( "
Algebra.Com's Answer #341223 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "1st Interger = x+2
\n" ); document.write( "2nd Integer = x+4
\n" ); document.write( "3rd Integer = x+6
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\n" ); document.write( "Given
\n" ); document.write( "5(x+2)+6(x+4)+7(x+6)=148
\n" ); document.write( "5x+10+6x+24+7x+42=148
\n" ); document.write( "18x+76=148
\n" ); document.write( "18x=148-76
\n" ); document.write( "18x=72
\n" ); document.write( "18x/18=72/18
\n" ); document.write( "x=4
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\n" ); document.write( "1st Integer = x+2 =4+2=6
\n" ); document.write( "2nd Integer = x+4 = 4+4=8
\n" ); document.write( "3rd Integer = x+6 = 4+6=10
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\n" ); document.write( "Check
\n" ); document.write( "(5*6)+6*(8)+7*(10)=148
\n" ); document.write( "30+48+70=148
\n" ); document.write( "148=148
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