document.write( "Question 508966: A parking meter will accept dimes and quarters only. At the end of the day, the meter attendants collected 55 coins whose total value was $10.75. How many coins of each type where there? \n" ); document.write( "
Algebra.Com's Answer #341197 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! d = number of dimes \n" ); document.write( "10d = value of the dimes in cents \n" ); document.write( "q = number of quarters \n" ); document.write( "24q = value of the quarters in cents \n" ); document.write( ". \n" ); document.write( "d + q = 55 \n" ); document.write( "so \n" ); document.write( "d = 55-q \n" ); document.write( ". \n" ); document.write( "10d + 25q = 1075 cents \n" ); document.write( ". \n" ); document.write( "substitute d = 55-q \n" ); document.write( ". \n" ); document.write( "10(55-q) + 25q = 1075 \n" ); document.write( "550 -10q + 25q = 1075 \n" ); document.write( "15q = 525 \n" ); document.write( "q = 35 \n" ); document.write( ". \n" ); document.write( "d = 55-q \n" ); document.write( "d = 55-35 \n" ); document.write( "d = 20 \n" ); document.write( ". \n" ); document.write( "Check to determine if the value is correct. \n" ); document.write( "25(35) = 875 cents \n" ); document.write( "10(20) = 200 cents \n" ); document.write( "875 + 200 = 1075 cents \n" ); document.write( "Correct. \n" ); document.write( ". \n" ); document.write( "Answer: The meter had 35 quarters and 20 dimes. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |