document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=508922>Question 508922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> this question is in my saxon algebra 3 book and i cant figure it out \r<BR>\n" );
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document.write( "find the surface area of a right circular cone whose slant height is 12 in and whos base has a radius of 5 in </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341175 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341175\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the surface area of a right circulr cone: <BR>\n" );
document.write( "Note:<BR>\n" );
document.write( "The \"lateral surface\" area (S) of a cone does not include the area of the base.<BR>\n" );
document.write( "The \"total surface\" (T) area of a cone included the area of the base.<BR>\n" );
document.write( "Let's do both and you can choose which anwer is appropriate.<BR>\n" );
document.write( "1) Lateral surface area (area of base not included) is:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S+=+pi%2Ar%2As ALIGN=MIDDLE  ALT=\"S+=+pi%2Ar%2As\"   DISABLED_style= \"max-width:90%; height:auto;\" > where: r is the radius of the base and s is the slant height.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S+=+pi%2A5%2A12 ALIGN=MIDDLE  ALT=\"S+=+pi%2A5%2A12\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S+=+60%2Api ALIGN=MIDDLE  ALT=\"S+=+60%2Api\"   DISABLED_style= \"max-width:90%; height:auto;\" > sq.in. This is the exact answer.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S+=+188.4 ALIGN=MIDDLE  ALT=\"S+=+188.4\"   DISABLED_style= \"max-width:90%; height:auto;\" > sq.in. This an approximate answer. (I just multiplied by 3.14 for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi ALIGN=MIDDLE  ALT=\"pi\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "2) Total surface area (area of base is included) is:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=T+=+pi%2Ar%28r%2Bs%29 ALIGN=MIDDLE  ALT=\"T+=+pi%2Ar%28r%2Bs%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > where: r is the radius of the base and s is the slant height.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=T+=+pi%2A5%285%2B12%29 ALIGN=MIDDLE  ALT=\"T+=+pi%2A5%285%2B12%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=T+=+pi%2A5%2817%29 ALIGN=MIDDLE  ALT=\"T+=+pi%2A5%2817%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=T+=+85%2Api ALIGN=MIDDLE  ALT=\"T+=+85%2Api\"   DISABLED_style= \"max-width:90%; height:auto;\" > sq.in. This is the exact answer.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=T+=+266.9 ALIGN=MIDDLE  ALT=\"T+=+266.9\"   DISABLED_style= \"max-width:90%; height:auto;\" > sq.in. This an approximate answer. (I just multiplied by 3.14).<BR>\n" );
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