document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=508922>Question 508922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> this question is in my saxon algebra 3 book and i cant figure it out \r<BR>\n" );
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document.write( "find the surface area of a right circular cone whose slant height is 12 in and whos base has a radius of 5 in </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341174 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> slant height is 12 inches and base has a radius of 5 inches.<BR>\n" );
document.write( "the surface area of the right circular cone will be pi*5*12 = 60*pi.<BR>\n" );
document.write( "here's a nifty little calculator on the web that calculates it for you.<BR>\n" );
document.write( "<a  rel=nofollow HREF= \"http://www.analyzemath.com/Geometry_calculators/surface_volume_cone.html\" target = \"_blank\">http://www.analyzemath.com/Geometry_calculators/surface_volume_cone.html</a><BR>\n" );
document.write( "you have to input the height though.<BR>\n" );
document.write( "the formula is:<BR>\n" );
document.write( "surface area of a right circular cone = pi*r*sqrt(r^2+h^2)<BR>\n" );
document.write( "r is the radius<BR>\n" );
document.write( "h is the height.<BR>\n" );
document.write( "sqrt(r^2+h^2) turns out to be the slant height which you already have.<BR>\n" );
document.write( "if you want to enter numbers into the calculator, you have to find the height.<BR>\n" );
document.write( "the pythagorean formula does that.<BR>\n" );
document.write( "a^2 + b^2 = c^2<BR>\n" );
document.write( "a and b are legs.<BR>\n" );
document.write( "c is the hypotenuse.<BR>\n" );
document.write( "in your right circular cone, the radius is a and the height is b and the slant height is c.<BR>\n" );
document.write( "your formula of a^2 + b^2 + c^2 becomes:<BR>\n" );
document.write( "5^2 + b^2 = 12^2<BR>\n" );
document.write( "solving for b gets b = sqrt(12^2 - 5^2) which comes out to be sqrt(119) which comes out to be 10.90871211.<BR>\n" );
document.write( "if you are to use this calculator, enter 10.90871211 as the radius.<BR>\n" );
document.write( "the calculator will tell you that the answer is 188.49556.<BR>\n" );
document.write( "60*pi comes out to be 188.4955592 which rounds to 188.49556.<BR>\n" );
document.write( "bottom line is the calculator and the equation i showed you above3 are the same.<BR>\n" );
document.write( "the surface area is pi * r * slant height.<BR>\n" );
document.write( "the calculator formula of sqrt(r^2 + h^2) is the formula for finding the slant height which you already had.\r<BR>\n" );
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