document.write( "Question 508935: A lab tech has one solution that is 45% acid and another that is 70 % acid. How much of each is needed to make 100 mL of a 65% acid solution? \n" ); document.write( "
Algebra.Com's Answer #341173 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A lab tech has one solution that is 45% acid and another that is 70 % acid. \n" ); document.write( "How much of each is needed to make 100 mL of a 65% acid solution? \n" ); document.write( "---- \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.45x + 0.70(100-x) = 0.65*100 \n" ); document.write( "----- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "45x + 70*100 - 70x = 65*100 \n" ); document.write( "5*100 = 25x \n" ); document.write( "x = 20 mL (amt of 45% solution needed) \n" ); document.write( "100-x = 80 mL (amt of 70% solution needed) \n" ); document.write( "============================================ \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " \n" ); document.write( " |