document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=508891>Question 508891</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The lengths of the three sides of a trianlge are in the ratio 3:5:6. The perimeter of the triangle is 21 cm. How can you find the length of each side of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341163 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341163\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 'x' be the unknown measurement.<BR>\n" );
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document.write( "Perimeter of a triangle = sum of sides.<BR>\n" );
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document.write( "3x + 5x + 6x = 21<BR>\n" );
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document.write( "14x = 21<BR>\n" );
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document.write( "x = 21/14 = 3/2<BR>\n" );
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document.write( "3x = 3(3/2) = 9/2<BR>\n" );
document.write( "5x = 5(3/2) = 15/2<BR>\n" );
document.write( "6x = 6(3/2) = 18/2<BR>\n" );
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document.write( "9/2 + 15/2 + 18/2 = 42/2 = 21<BR>\n" );
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document.write( "The three sides are:  9/2, 15/2 and 18/2<BR>\n" );
document.write( "or 4.5, 7.5, and 9.<BR>\n" );
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document.write( "Done. </SPAN>\n" );
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