document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=508881>Question 508881</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Contains (5,1) and is parallel to y=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341159 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341159\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have a line that is horizontal and it follows that its slope is 0. This means that a line parallel to this line also has slope 0 and is in fact a horizontal line.  We will expect that this line will be of the form  y = (some number). And since our coordinate is (5,1) [implying that y = 1], a good guess would be that the line is y =1. Let's solve this algebraically.\r<BR>\n" );
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document.write( "We have a slope and we have a point. Let's use point-slope form.\r<BR>\n" );
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document.write( "y - y1 = m(x-x1)\r<BR>\n" );
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document.write( "y - 1 = 0(x-5)\r<BR>\n" );
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document.write( "y - 1 = 0\r<BR>\n" );
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document.write( "y = 1 <--- Just as we expected.\r<BR>\n" );
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