document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=508847>Question 508847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> pls answer my word problems..............<BR>\n" );
document.write( "two pipes together can fill a large tank in 2 hours. one of the pipes, used alone, takes 3 hours longer than the other to fill the tank. how long would each pipe take to fill the tank alone.<BR>\n" );
document.write( "FASTER PIPE: RATE:1/x IN 2 HRS.<BR>\n" );
document.write( "SLOWER PIPE: RATE:????? IN 2 hrs. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341142 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341142\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> With work problems like this, each device does a fraction of the whole job.<BR>\n" );
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document.write( "One pipe has an unknown rate, so it does 1/x job per hr.<BR>\n" );
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document.write( "One pipe does the job in 3 more hr than the other one, so it does 1/(x+3) job per hr.<BR>\n" );
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document.write( "Working together they get the whole job done in 2 hrs.<BR>\n" );
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document.write( "( 1/x + 1/(x+3) ) * 2 = 1 whole job<BR>\n" );
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document.write( "(x+3 +x ) / x(x+3) = 1/2<BR>\n" );
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document.write( "cross multiply<BR>\n" );
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document.write( "2(2x+3) = x(x+3)<BR>\n" );
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document.write( "4x +6 = x^2 + 3x<BR>\n" );
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document.write( "x^2 +3x = 4x +6<BR>\n" );
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document.write( "x^2 +3x -4x = 6<BR>\n" );
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document.write( "x^2 -x -6 = 0<BR>\n" );
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document.write( "factor<BR>\n" );
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document.write( "(x-3)(x+2) = 0<BR>\n" );
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document.write( "so x=3 or x=-2<BR>\n" );
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document.write( "-2 is nonsense, so the only realistic answer is x=3<BR>\n" );
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document.write( "One pipe does the work in 3 hr, so it does 1/3 job per hr.<BR>\n" );
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document.write( "The other takes 3 hr longer, so it takes 6 hr, or 1/6 job per hr.<BR>\n" );
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document.write( "Check to see if they can do the job in 2 hr working together.<BR>\n" );
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document.write( "(1/3 + 1/6) *2 = ?<BR>\n" );
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document.write( "(2/6 + 1/6) = 3/6<BR>\n" );
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document.write( "3/6*2 = 6/6 = 1<BR>\n" );
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document.write( "Correct.  the two can do 1 whole job in 2 hrs working together.<BR>\n" );
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document.write( "Answer:  Working alone, the faster pipe can do the work in 3 hrs; the slower pipe can do the work in 6 hrs.<BR>\n" );
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document.write( "Done.<BR>\n" );
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