document.write( "Question 508791: How many liters of pure dye must be added to 45 liters of a 6% dye solution to obtain a 10% dye solution? \n" ); document.write( "
Algebra.Com's Answer #341106 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! Always keep track of how much 'pure' stuff you need. \n" ); document.write( ". \n" ); document.write( "You have 45 liters of 6% solution, so it contains .06*45 = 2.7 liters of pure dye in solution \n" ); document.write( ". \n" ); document.write( "You need to add 'x' liters of pure dye. \n" ); document.write( ". \n" ); document.write( "6%(45) + 100%(x) = 10%(45+x) \n" ); document.write( ". \n" ); document.write( ".06(45) + 1.00(x) = .10(45+x) \n" ); document.write( ". \n" ); document.write( "multiply through by 100 to get rid of decimals \n" ); document.write( ". \n" ); document.write( "6(45) + 100x = 10(45+x) \n" ); document.write( ". \n" ); document.write( "270 +100x = 450 +10x \n" ); document.write( ". \n" ); document.write( "subtract 270 from both sides \n" ); document.write( ". \n" ); document.write( "100x = 180 +10x \n" ); document.write( ". \n" ); document.write( "subtract 10x from both sides \n" ); document.write( ". \n" ); document.write( "90x = 180 \n" ); document.write( ". \n" ); document.write( "divide both sides by 90 \n" ); document.write( ". \n" ); document.write( "x = 2 \n" ); document.write( ". \n" ); document.write( "Add 2 liters of pure dye to obtain 47 liters of 10% dye. \n" ); document.write( ". \n" ); document.write( "Check the amount of pure dye. \n" ); document.write( ". \n" ); document.write( ".10*47 = 4.7 liters of dye are supposed to be in 47 liters of 10% solution. \n" ); document.write( "In the original 45 liters we found we had 2.7 liters (.06*45) of pure dye. \n" ); document.write( "So, adding 2 liters of pure dye does it. \n" ); document.write( ". \n" ); document.write( "Answer: Add 2 liters of pure dye. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " \n" ); document.write( " |