document.write( "Question 508723: Can someone help me solve this question?
\n" ); document.write( "The length of a rectangle is twice the width. The area is 48 square inches. What is the perimeter?
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Algebra.Com's Answer #341077 by jerryguo41(197)\"\" \"About 
You can put this solution on YOUR website!
l=length
\n" ); document.write( "w=width
\n" ); document.write( "\"l=2w\" (length equals twice the width)
\n" ); document.write( "area
\n" ); document.write( "\"l%2Aw=48\"
\n" ); document.write( "plug in
\n" ); document.write( "\"l=2w\"
\n" ); document.write( "\"2w%2Aw=48\"
\n" ); document.write( "Solve
\n" ); document.write( "\"2w%5E2=48\"
\n" ); document.write( "Divide
\n" ); document.write( "\"w%5E2=24\"
\n" ); document.write( "Sqrt
\n" ); document.write( "\"w=sqrt%2824%29\"
\n" ); document.write( "Simplify
\n" ); document.write( "\"w=2sqrt%286%29\"
\n" ); document.write( "Solve for l
\n" ); document.write( "\"l=%282sqrt%286%29%29%2F2\"
\n" ); document.write( "\"l=sqrt%286%29\"\r
\n" ); document.write( "\n" ); document.write( "Perimeter
\n" ); document.write( "\"2l%2B2w\"
\n" ); document.write( "\"2%28sqrt%286%29%29%2B2%282sqrt%286%29%29\"
\n" ); document.write( "\"6sqrt%286%29\"
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