document.write( "Question 507911: The equation e^ { 2 x } - 11 e^ { x } +30 = 0 has two solutions. \r
\n" ); document.write( "\n" ); document.write( "The smaller one is:
\n" ); document.write( "and the larger one is:
\n" ); document.write( "

Algebra.Com's Answer #341055 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
The equation e^ { 2 x } - 11 e^ { x } +30 = 0 has two solutions.
\n" ); document.write( "The smaller one is:
\n" ); document.write( "and the larger one is:
\n" ); document.write( "**
\n" ); document.write( "e^ { 2 x } - 11 e^ { x } +30 = 0
\n" ); document.write( "e^2x-11^x+30=0
\n" ); document.write( "let u=e^x
\n" ); document.write( "u^2=e^2x
\n" ); document.write( "u^2-11u+30=0
\n" ); document.write( "(u-6)(u-5)=0
\n" ); document.write( "u=6
\n" ); document.write( "or
\n" ); document.write( "u=5
\n" ); document.write( "...
\n" ); document.write( "for u=6
\n" ); document.write( "e^x=6
\n" ); document.write( "take ln of both sides
\n" ); document.write( "lne^x=ln6
\n" ); document.write( "x=1.7918
\n" ); document.write( "..
\n" ); document.write( "for u=5
\n" ); document.write( "e^x=5
\n" ); document.write( "take ln of both sides
\n" ); document.write( "lne^x=ln5
\n" ); document.write( "x=1.6094
\n" ); document.write( "..
\n" ); document.write( "ans:
\n" ); document.write( "x=1.7918
\n" ); document.write( "and
\n" ); document.write( "x=1.6094
\n" ); document.write( "
\n" );