document.write( "Question 507911: The equation e^ { 2 x } - 11 e^ { x } +30 = 0 has two solutions. \r
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document.write( "The smaller one is:
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document.write( "and the larger one is: \n" );
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Algebra.Com's Answer #341055 by lwsshak3(11628) ![]() You can put this solution on YOUR website! The equation e^ { 2 x } - 11 e^ { x } +30 = 0 has two solutions. \n" ); document.write( "The smaller one is: \n" ); document.write( "and the larger one is: \n" ); document.write( "** \n" ); document.write( "e^ { 2 x } - 11 e^ { x } +30 = 0 \n" ); document.write( "e^2x-11^x+30=0 \n" ); document.write( "let u=e^x \n" ); document.write( "u^2=e^2x \n" ); document.write( "u^2-11u+30=0 \n" ); document.write( "(u-6)(u-5)=0 \n" ); document.write( "u=6 \n" ); document.write( "or \n" ); document.write( "u=5 \n" ); document.write( "... \n" ); document.write( "for u=6 \n" ); document.write( "e^x=6 \n" ); document.write( "take ln of both sides \n" ); document.write( "lne^x=ln6 \n" ); document.write( "x=1.7918 \n" ); document.write( ".. \n" ); document.write( "for u=5 \n" ); document.write( "e^x=5 \n" ); document.write( "take ln of both sides \n" ); document.write( "lne^x=ln5 \n" ); document.write( "x=1.6094 \n" ); document.write( ".. \n" ); document.write( "ans: \n" ); document.write( "x=1.7918 \n" ); document.write( "and \n" ); document.write( "x=1.6094 \n" ); document.write( " |