document.write( "Question 507912: If e^ { 2 x } - 1 e^ { x } = + 2 \n" ); document.write( "
Algebra.Com's Answer #341052 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
solving for x
\n" ); document.write( "e^ { 2 x } - 1 e^ { x } = + 2
\n" ); document.write( "e^2x-e^x-2=0
\n" ); document.write( "let u=e^x
\n" ); document.write( "u^2=e^2x
\n" ); document.write( "u^2-u-2=0
\n" ); document.write( "(u-2)(u+1)=0
\n" ); document.write( "u=2
\n" ); document.write( "or u=-1
\n" ); document.write( "..
\n" ); document.write( "for u=-1
\n" ); document.write( "e^x≠-1
\n" ); document.write( "reject
\n" ); document.write( "..
\n" ); document.write( "for u=2
\n" ); document.write( "e^x=2
\n" ); document.write( "take ln of both sides
\n" ); document.write( "lne^x=ln2
\n" ); document.write( "x=.6931
\n" ); document.write( "
\n" );