document.write( "Question 507912: If e^ { 2 x } - 1 e^ { x } = + 2 \n" ); document.write( "
Algebra.Com's Answer #341052 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! solving for x \n" ); document.write( "e^ { 2 x } - 1 e^ { x } = + 2 \n" ); document.write( "e^2x-e^x-2=0 \n" ); document.write( "let u=e^x \n" ); document.write( "u^2=e^2x \n" ); document.write( "u^2-u-2=0 \n" ); document.write( "(u-2)(u+1)=0 \n" ); document.write( "u=2 \n" ); document.write( "or u=-1 \n" ); document.write( ".. \n" ); document.write( "for u=-1 \n" ); document.write( "e^x≠-1 \n" ); document.write( "reject \n" ); document.write( ".. \n" ); document.write( "for u=2 \n" ); document.write( "e^x=2 \n" ); document.write( "take ln of both sides \n" ); document.write( "lne^x=ln2 \n" ); document.write( "x=.6931 \n" ); document.write( " |