document.write( "Question 508540: The product of the first and third of three consecutive integers is 3 more than 3 times the second integer. Find the integers. \n" ); document.write( "
Algebra.Com's Answer #341028 by swincher4391(1107)\"\" \"About 
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Let n be the first, n+1 be the second, n+2 be the third.\r
\n" ); document.write( "\n" ); document.write( "Then n*(n+2) = 3 + 3(n+1)\r
\n" ); document.write( "\n" ); document.write( "n^2 + 2n = 3 +3n +3\r
\n" ); document.write( "\n" ); document.write( "n^2 - n - 6 = 0\r
\n" ); document.write( "\n" ); document.write( "(n+2)*(n-3)\r
\n" ); document.write( "\n" ); document.write( "n = -2 n =3\r
\n" ); document.write( "\n" ); document.write( "I'm assuming we're talking about positive integers, so then our integers are 3, 4,5 <--- Answers
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