document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=508510>Question 508510</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i was given this example to work with...\r<BR>\n" );
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document.write( "\"if 3 apples and 2 pears cost $6.00 and 7 apples and 6 pears cost $15.00, how much will one apple and one pear cost?\" \r<BR>\n" );
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document.write( "given solution: \r<BR>\n" );
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document.write( "3a+2p=6.00<BR>\n" );
document.write( "7a+6p=15.00\r<BR>\n" );
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document.write( "\"because these two equations do not have the same 'y' value, they must be changed in order to eliminate one of the variables.\"\r<BR>\n" );
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document.write( "(this is where i ran into trouble)\r<BR>\n" );
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document.write( "-3(3a+2p=6.00)=-9a - 6p=-18.00\r<BR>\n" );
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document.write( "(everything i understand perfectly up until this point. i just dont how to come to the '-3' there infront of the sum. where did it come from? and how do i know whether its even suppose to be a negative or a three for that matter? please please any help would be greatly appreciated. my final graduating year depends on my completing this last book.)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341027 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341027\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if 3 apples and 2 pears cost $6.00 and 7 apples and 6 pears cost $15.00, how much will one apple and one pear cost?\" <BR>\n" );
document.write( "given solution: <BR>\n" );
document.write( "3a+2p=6.00<BR>\n" );
document.write( "7a+6p=15.00 <BR>\n" );
document.write( "\"because these two equations do not have the same 'y' value, they must be changed in order to eliminate one of the variables.\" <BR>\n" );
document.write( "(this is where i ran into trouble) <BR>\n" );
document.write( "-3(3a+2p=6.00)=-9a - 6p=-18.00 <BR>\n" );
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document.write( "3a+2p=600<BR>\n" );
document.write( "7a+6p=1500 <BR>\n" );
document.write( "Multiply the 1st eqn by -3<BR>\n" );
document.write( "-9a - 6p = -1800<BR>\n" );
document.write( "+7a + 6p = 1500<BR>\n" );
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document.write( "-2a = -300<BR>\n" );
document.write( "a = 150 cents, etc.<BR>\n" );
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document.write( "You were doing the right thing, just didn't finish it.\r<BR>\n" );
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