document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=508543>Question 508543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find a so that the graph of f(x) = loga(x) contains the point (1/3, -6). Give your answer correct to 2 decimal places. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #341026 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=341026\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Basically, this question is asking  a^-6 = 1/3 for what value of a satisfies this equation?\r<BR>\n" );
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document.write( "Well, to solve this we must *undo* a^-6 by raising it to the -1/6 power.\r<BR>\n" );
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document.write( "(a^-6)^(-1/6)  =  (1/3)^(-1/6) =  1.20 <---- Answer\r<BR>\n" );
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document.write( "To check,   we put in  log(1/3) / log(1.2)  [change of base formula] and we get roughly -6, since we rounded our base to 1.20.\r<BR>\n" );
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document.write( "Thus a = 1.20\r<BR>\n" );
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document.write( "Hopefully this helped!\r<BR>\n" );
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document.write( "If this was not clear, please e-mail me at onlyyourmathtutor@yahoo.com.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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