document.write( "Question 508467: it takes 3 hours for a boat to ravel 27 mile upstram. the same boat can travel 30 miles down stream in 2 hours fond the speed of the boat and the current \n" ); document.write( "
Algebra.Com's Answer #341021 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Speed of boat = b
\n" ); document.write( "Speed of current = c\r
\n" ); document.write( "\n" ); document.write( "Given\r
\n" ); document.write( "\n" ); document.write( "Upstream
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\n" ); document.write( "Distance = 27 miles
\n" ); document.write( "Time = 3 hours\r
\n" ); document.write( "\n" ); document.write( "Speed = Distance/time
\n" ); document.write( "Speed = 27/3
\n" ); document.write( "Speed = 9 miles per hour
\n" ); document.write( "We can say boat speed minus the speed of current
\n" ); document.write( "b-c=9..........(1)\r
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\n" ); document.write( "\n" ); document.write( "Downstream
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\n" ); document.write( "Distance = 30 hours
\n" ); document.write( "Time = 2 hours
\n" ); document.write( "Speed = Distance/time
\n" ); document.write( "Speed = 30/2
\n" ); document.write( "Speed = 15 miles per hour
\n" ); document.write( "We can say boat speed plus the speed of current
\n" ); document.write( "b+c=15.............(2)\r
\n" ); document.write( "\n" ); document.write( "Add (1) and (2)
\n" ); document.write( "b-c=9..........(1)
\n" ); document.write( "b+c=15.............(2)
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\n" ); document.write( "2b=24
\n" ); document.write( "b=24/2
\n" ); document.write( "b=12\r
\n" ); document.write( "\n" ); document.write( "Put the value of b in (2)
\n" ); document.write( "b+c=15.............(2)
\n" ); document.write( "12+c=15
\n" ); document.write( "c=15-12
\n" ); document.write( "c=3
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\n" ); document.write( "Speed of boat = b = 12 miles / hour
\n" ); document.write( "Speed of current = c = 3 miles / hour\r
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