document.write( "Question 506885: consider an arithmetc sequence whose fourth entry is 2 and whose seventh entry is 4. find the first and second entries of the sequence. \n" ); document.write( "
Algebra.Com's Answer #341009 by Maths68(1474) You can put this solution on YOUR website! 4th term = 2 \n" ); document.write( "7th term = 4 \n" ); document.write( "First term = ? \n" ); document.write( "Second term = ? \n" ); document.write( "Use \n" ); document.write( "Tn=a+(n-1)d \n" ); document.write( "Where \n" ); document.write( "Tn = Term \n" ); document.write( "n = Term number \n" ); document.write( "a = First term \n" ); document.write( "d = Common Difference\r \n" ); document.write( "\n" ); document.write( "======================================== \n" ); document.write( "For 4th term \n" ); document.write( "a=?, d=?, Tn=2, n=4 \n" ); document.write( "Tn=a+(n-1)d \n" ); document.write( "Put the values in above formula \n" ); document.write( "2=a+(4-1)d \n" ); document.write( "2=a+(3)d \n" ); document.write( "2=a+3d ................(1) \n" ); document.write( "========================================= \n" ); document.write( "For 7th term \n" ); document.write( "a=?, d=?, Tn=4, n=7 \n" ); document.write( "Tn=a+(n-1)d \n" ); document.write( "Put the values in above formula \n" ); document.write( "4=a+(7-1)d \n" ); document.write( "4=a+(6)d \n" ); document.write( "4=a+6d...............(2) \n" ); document.write( "========================================= \n" ); document.write( "Subtract (1) from (2) \n" ); document.write( "4=a+6d...............(2) \n" ); document.write( "-2=-a-3d ................(1) \n" ); document.write( "-------------- \n" ); document.write( "2=3d \n" ); document.write( "2/3=d \n" ); document.write( "Put the value of d in (1) \n" ); document.write( "2=a+3d ................(1) \n" ); document.write( "2=a+3*(2/3) \n" ); document.write( "2=a+2 \n" ); document.write( "2-2=a \n" ); document.write( "a=0\r \n" ); document.write( "\n" ); document.write( "First term = 0 \n" ); document.write( "Now \n" ); document.write( "For 2nd Term \n" ); document.write( "Tn=a+(n-1)d \n" ); document.write( "Tn=0+(2-1)2/3 \n" ); document.write( "Tn=2/3 \n" ); document.write( "For 3rd Term \n" ); document.write( "Tn=0+(3-1)2/3 \n" ); document.write( "Tn=0+(3-1)2/3 \n" ); document.write( "Tn=4/3 \n" ); document.write( "For 4th Term \n" ); document.write( "Tn=0+(4-1)2/3 \n" ); document.write( "Tn=0+(3)2/3 \n" ); document.write( "Tn=2 \n" ); document.write( "and so on ............\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Required A.P \n" ); document.write( "0,2/3,4/3, 2,.............\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |