document.write( "Question 508414: A roofer and his assistant working together can finish a roofing job in 4 hours. The roofer working alone could finish the job in 6 hours less than the assistant working alone. How long would it take the roofer working alone?\r
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Algebra.Com's Answer #340992 by nerdybill(7384) You can put this solution on YOUR website! A roofer and his assistant working together can finish a roofing job in 4 hours. The roofer working alone could finish the job in 6 hours less than the assistant working alone. How long would it take the roofer working alone? \n" ); document.write( ". \n" ); document.write( "Let x = time (hours) for assistant alone \n" ); document.write( "then \n" ); document.write( "x-6 = time (hours) for roofer \n" ); document.write( ". \n" ); document.write( "4(1/x + 1/(x-6)) = 1 \n" ); document.write( "multiplying both sides by x(x-6): \n" ); document.write( "4((x-6) + x) = x(x-6) \n" ); document.write( "4(2x-6) = x^2-6x \n" ); document.write( "8x-24 = x^2-6x \n" ); document.write( "-24 = x^2-14x \n" ); document.write( "0 = x^2-14x+24 \n" ); document.write( "0 = (x-2)(x-12) \n" ); document.write( "x = {2,12} \n" ); document.write( "we can throw out the 2 (extraneous) leaving: \n" ); document.write( "x = 12 hours (assistant) \n" ); document.write( ". \n" ); document.write( "Roofer working alone: \n" ); document.write( "x-6 = 12-6 = 6 hours\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |