document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=508439>Question 508439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A carpenter is building a rectangular room with a fixed perimeter of 324 ft.  What dimentions would yield the maximum area?  What is the maximum area?  I understand the formula P=2l+2w will help solve this, but am unsure how to find the length and width.  Any help you can give is greatly appreciated.  Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340989 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A carpenter is building a rectangular room with a fixed perimeter of 324 ft. What dimentions would yield the maximum area? What is the maximum area?<BR>\n" );
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document.write( "2(L + W) = 324<BR>\n" );
document.write( "L+W = 162<BR>\n" );
document.write( "L = (162-W)<BR>\n" );
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document.write( "Area = LW<BR>\n" );
document.write( "Area = (162-W)W<BR>\n" );
document.write( "A = 162W-W^2<BR>\n" );
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document.write( "You have a quadratic equation with a = -1, b = 162, c = -A<BR>\n" );
document.write( "Maximum Area occurs when W = -b/(2a) = -162/(2*-1) = 81 ft.<BR>\n" );
document.write( "--<BR>\n" );
document.write( "Solve for \"L\":<BR>\n" );
document.write( "L + W = 162<BR>\n" );
document.write( "L = 162-81 = 81 ft.<BR>\n" );
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document.write( "Maximum Area = 81^2 = 6561 sq. ft.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );