document.write( "Question 508313: A motorboat traveling with the current went 72 km in 3 h. Against the current the boat could go only 48 km in the same amount of time. Find the rate of the boat in calm water and the rate of the current. \n" ); document.write( "

Algebra.Com's Answer #340951 by mananth(16946) $\"\"$ $\"About$

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Boat speed= x mph
\n" ); document.write( "current speed= y mph
\n" ); document.write( "with current speed= (x+y)
\n" ); document.write( "against current speed= (x-y)
\n" ); document.write( "d= 72 with current
\n" ); document.write( "72 / (x+y) = 3
\n" ); document.write( "divide by 3
\n" ); document.write( "24 / (x+y) = 1
\n" ); document.write( "(x+y) = 24 ............1
\n" ); document.write( "d= = 48 against current
\n" ); document.write( "27/(x-y) = 3
\n" ); document.write( "divide by 3
\n" ); document.write( "48 /(x-y) = 3
\n" ); document.write( " x - y = 16 .............2
\n" ); document.write( "add up (1) & (2)
\n" ); document.write( "2 x = 40
\n" ); document.write( "/ 2
\n" ); document.write( "x= 20 mph speed of Boat in still water
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "we get y= 4 mph speed of current
\n" ); document.write( " \n" ); document.write( "

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