document.write( "Question 508088: One solution is 10% acid, another solution is 30% acid. find the volume of each solution that must be used to get a final solution of 40 liters that is 18% acid. \n" ); document.write( "

Algebra.Com's Answer #340946 by Maths68(1474) $\"\"$ $\"About$

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Solution A
\n" ); document.write( "Amount = x ?
\n" ); document.write( "Concentration = 10% = 0.1
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\n" ); document.write( "Solution B
\n" ); document.write( "Amount =40- x ?
\n" ); document.write( "Concentration =30% = 0.3
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\n" ); document.write( "Resultant Solution
\n" ); document.write( "Amount = 40 liters
\n" ); document.write( "Concentration = 18%=0.18
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\n" ); document.write( "[Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B] = Amount of Resultant * Concentration of resultant
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\n" ); document.write( "Put the value in above equation
\n" ); document.write( "(x*0.1)+((40-x)*0.3=40*0.18
\n" ); document.write( "0.1x+12-0.3x=7.2
\n" ); document.write( "0.1x+12-0.3x=7.2
\n" ); document.write( "-0.2x=7.2-12
\n" ); document.write( "-0.2x=-4.8
\n" ); document.write( "Divide by (-0.2) both sides
\n" ); document.write( "-0.2x/-0.2=-4.8/-0.2
\n" ); document.write( "x=24 liters
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\n" ); document.write( "Amount of solution A = 24 liters
\n" ); document.write( "Amount of Sultion B = 40-24=16 liters
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