document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=508303>Question 508303</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the inverse operation of<BR>\n" );
document.write( "1. divide by 8?<BR>\n" );
document.write( "2. divide by -5?<BR>\n" );
document.write( "3 multiply by 10?<BR>\n" );
document.write( "4. multiply by 1/2?<BR>\n" );
document.write( "5. divide by -2/3?<BR>\n" );
document.write( "6. multiply by -6/5?<BR>\n" );
document.write( "7. add 18?<BR>\n" );
document.write( "8. add -11?<BR>\n" );
document.write( "9. subtract 31?<BR>\n" );
document.write( "10. subtract -25?<BR>\n" );
document.write( "11. subtract -4 1/2?<BR>\n" );
document.write( "12. subtract -10.06\r<BR>\n" );
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document.write( "thank you so much, and please answer all twelve :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340926 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340926\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The inverse of adding is subtracting, and the inverse of subtracting is adding (by the same amount).\r<BR>\n" );
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document.write( "The inverse of multiplying is dividing, and the inverse of dividing is multiplying.\r<BR>\n" );
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document.write( "That should carry you through each problem. </SPAN>\n" );
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