document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=508289>Question 508289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the square root of ? sqrt(63)+sqrt(7)= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340918 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using a calculator one will get 10.583.\r<BR>\n" );
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document.write( "One could estimate this though:\r<BR>\n" );
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document.write( "sqrt(63) is going to be just slightly under 8 [sqrt(64)].  Let's call it 7.9\r<BR>\n" );
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document.write( "sqrt(7) is going to be under 3 [sqrt(9)], but moreso than what sqrt(63) was to sqrt(64)  Let's call it 2.6 maybe 2.7.\r<BR>\n" );
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document.write( "7.9 + 2.6 = 10.5<BR>\n" );
document.write( "7.9 + 2.7 = 10.6  \r<BR>\n" );
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document.write( "So it's between 10.5 and 10.6 ... not a bad estimate right?\r<BR>\n" );
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document.write( "I hope this helped.\r<BR>\n" );
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document.write( "If you have more questions, or this didn't help, please e-mail me at onlyyourmathtutor@yahoo.com. </SPAN>\n" );
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